This question was previously asked in

MPPEB Stenographer 31 July 2018 Shift 1 Official Paper

- αβγ = -2; α + β + γ = 2
- αβγ = 2; α + β + γ = -1
- αβγ = -1; α + β + γ = -2
- αβγ = 2; α + β + γ = -2

Option 1 : αβγ = -2; α + β + γ = 2

**Given **

p(γ) = y3 - 2y2 - y + 2

**Concept Used **

In cubic equation

ax^{3} + bx^{2} + cx + d = 0 if roots are p, q and r

Sum of roots = p + q + r = -b/a

Product of roots = pqr = -d/a

**Calculation **

According to the question

α,β,γ are the zeros of the polynomial p(γ) = y3 - 2y2 - y + 2

Then α + β + γ = -(-2)/1 = 2

Also, αβγ = -2/1 = -2

**∴ The required answer is αβγ = -2; α + β + γ = 2**

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