Bringing It Together: Homework
A previous year, the weights of the members of a California football team and a Texas football team were published in a newspaper The factual data are compiled into Table 3.25. The weights in the column headings are in pounds.
Shirt# | ≤ 210 | 211–250 | 251–290 | 290≤ |
---|---|---|---|---|
1–33 | 21 | 5 | 0 | 0 |
34–66 | 6 | 18 | 7 | 4 |
66–99 | 6 | 12 | 22 | 5 |
For the following, suppose that you randomly select one player from the California team or the Texas team.
If having a shirt number from one to 33 and weighing at most 210 pounds were independent events, then what should be true about P(Shirt# 1–33|≤ 210 pounds)?
The probability that a male develops some form of cancer in his lifetime is .4567. The probability that a male has at least one false-positive test result, meaning the test comes back for cancer when the man does not have it, is .51. Some of the following questions do not have enough information for you to answer them. Write not enough information for those answers. Let C = a man develops cancer in his lifetime and P = a man has at least one false-positive.
- P(C) = ______
- P(P|C) = ______
- P(P|C') = ______
- If a test comes up positive, based upon numerical values, can you assume that man has cancer? Justify numerically and explain why or why not.
Given events G and H: P(G) = .43; P(H) = .26; P(H AND G) = .14
- Find P(H OR G).
- Find the probability of the complement of event (H AND G).
- Find the probability of the complement of event (H OR G).
Given events J and K: P(J) = .18; P(K) = .37; P(J OR K) = .45
- Find P(J AND K).
- Find the probability of the complement of event (J AND K).
- Find the probability of the complement of event (J OR K).
Use the following information to answer the next two exercises: Suppose that you have eight cards. Five are green and three are yellow. The cards are well shuffled.
Suppose that you randomly draw two cards, one at a time, with replacement.
- Draw a tree diagram of the situation.
- Find P(G1 AND G2).
- Find P(at least one green).
- Find P(G2|G1).
- Are G2 and G1 independent events? Explain why or why not.
Suppose that you randomly draw two cards, one at a time, without replacement.
- Draw a tree diagram of the situation.
- Find P(G1 AND G2).
- Find P(at least one green).
- Find P(G2|G1).
- Are G2 and G1 independent events? Explain why or why not.
Use the following information to answer the next two exercises: The percent of licensed U.S. drivers (from a recent year) who are female is 48.60. Of the females, 5.03 percent are age 19 and under; 81.36 percent are age 20–64; 13.61 percent are age 65 or over. Of the licensed U.S. male drivers, 5.04 percent are age 19 and under; 81.43 percent are age 20–64; 13.53 percent are age 65 or over.
Complete the following:
- Construct a table or a tree diagram of the situation.
- Find P(driver is female).
- Find P(driver is age 65 or over|driver is female).
- Find P(driver is age 65 or over AND female).
- In words, explain the difference between the probabilities in Part c and Part d.
- Find P(driver is age 65 or over).
- Are being age 65 or over and being female mutually exclusive events? How do you know?
Suppose that 10,000 U.S. licensed drivers are randomly selected.
- How many would you expect to be male?
- Using the table or tree diagram, construct a contingency table of gender versus age group.
- Using the contingency table, find the probability that out of the age 20–64 group, a randomly selected driver is female.
Approximately 86.5 percent of Americans commute to work by car, truck, or van. Out of that group, 84.6 percent drive alone and 15.4 percent drive in a carpool. Approximately 3.9 percent walk to work and approximately 5.3 percent take public transportation.
- Construct a table or a tree diagram of the situation. Include a branch for all other modes of transportation to work.
- Assuming that the walkers walk alone, what percent of all commuters travel alone to work?
- Suppose that 1,000 workers are randomly selected. How many would you expect to travel alone to work?
- Suppose that 1,000 workers are randomly selected. How many would you expect to drive in a carpool?
When the euro coin was introduced in 2002, two math professors had their statistics students test whether the Belgian one-euro coin was a fair coin. They spun the coin rather than tossing it and found that out of 250 spins, 140 showed a head (event H) while 110 showed a tail (event T). On that basis, they claimed that it is not a fair coin.
- Based on the given data, find P(H) and P(T).
- Use a tree to find the probabilities of each possible outcome for the experiment of spinning the coin twice.
- Use the tree to find the probability of obtaining exactly one head in two spins of the coin.
- Use the tree to find the probability of obtaining at least one head.
Use the following information to answer the next two exercises: The following are real data from Santa Clara County, California. As of a certain time, there had been a total of 3,059 documented cases of a disease in the county. They were grouped into the following categories, with risk factors of becoming ill with the disease labeled as Methods A, B, and C and Other:
Method A | Method B | Method C | Other | Totals | |
---|---|---|---|---|---|
Female | 0 | 70 | 136 | 49 | ____ |
Male | 2,146 | 463 | 60 | 135 | ____ |
Totals | ____ | ____ | ____ | ____ | ____ |
Suppose a person with a disease in Santa Clara County is randomly selected.
- Find P(Person is female).
- Find P(Person has a risk factor of method C).
- Find P(Person is female OR has a risk factor of method B).
- Find P(Person is female AND has a risk factor of method A).
- Find P(Person is male AND has a risk factor of method B).
- Find P(Person is female GIVEN person got the disease from method C).
- Construct a Venn diagram. Make one group females and the other group method C.
Answer these questions using probability rules. Do NOT use the contingency table. Three thousand fifty-nine cases of a disease had been reported in Santa Clara County, California, through a certain date. Those cases will be our population. Of those cases, 6.4 percent obtained the disease through method C and 7.4 percent are female. Out of the females with the disease, 53.3 percent got the disease from method C.
- Find P(Person is female).
- Find P(Person obtained the disease through method C).
- Find P(Person is female GIVEN person got the disease from method C).
- Construct a Venn diagram representing this situation. Make one group females and the other group method C. Fill in all values as probabilities.